MHT CET Ionic Equilibria Mock Test 2026 | Free Practice Quiz


MHT CET Ionic Equilibria Mock Test

Instructions:
  • Total Questions: 20 MCQs
  • Time Limit: 20 Minutes
  • No negative marking.
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Ionic Equilibria
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1. According to Arrhenius theory, an acid is a substance that:
a) Accepts a proton
b) Donates a lone pair of electrons
c) Gives H⁺ ions in aqueous solution
d) Accepts an electron pair
Solution: Arrhenius acids dissociate in water to give H⁺ ions.
2. Which of the following is a Lewis acid?
a) NH₃
b) BF₃
c) H₂O
d) OH⁻
Solution: BF₃ is electron-deficient (incomplete octet) and accepts an electron pair, acting as a Lewis acid.
3. The conjugate base of HSO₄⁻ is:
a) SO₄²⁻
b) H₂SO₄
c) H₃O⁺
d) HSO₃⁻
Solution: Conjugate base is formed by removing an H⁺. HSO₄⁻ - H⁺ = SO₄²⁻.
4. For pure water at 298 K, the value of Kw is:
a) 1 × 10⁻⁷
b) 1 × 10⁻¹⁰
c) 1 × 10⁻¹⁴
d) 14
Solution: Ionic product of water (Kw) at 25°C is 1 × 10⁻¹⁴.
5. The pH of 0.01 M HCl solution is:
a) 1
b) 2
c) 3
d) 12
Solution: [H⁺] = 0.01 = 10⁻² M. pH = -log(10⁻²) = 2.
6. Which relation is correct for an aqueous solution at 25°C?
a) pH + pOH = 7
b) pH × pOH = 14
c) pH - pOH = 14
d) pH + pOH = 14
Solution: The sum of pH and pOH is always 14 at 25°C.
7. A buffer solution is a mixture of:
a) Weak acid and its salt with strong base
b) Strong acid and strong base
c) Weak acid and weak base
d) Strong acid and its salt with weak base
Solution: An acidic buffer contains a weak acid and its salt with a strong base (e.g., CH₃COOH + CH₃COONa).
8. The pH of a solution is 5. Its pOH is:
a) 5
b) 7
c) 9
d) 14
Solution: pOH = 14 - pH = 14 - 5 = 9.
9. Solubility product (Ksp) of AgCl is expressed as:
a) [Ag⁺] + [Cl⁻]
b) [Ag⁺][Cl⁻]
c) [Ag⁺]/[Cl⁻]
d) [AgCl]
Solution: Ksp is the product of ion concentrations: Ksp = [Ag⁺][Cl⁻].
10. Which salt undergoes hydrolysis to form a basic solution?
a) NaCl
b) NH₄Cl
c) CH₃COONa
d) K₂SO₄
Solution: CH₃COONa is a salt of Weak Acid + Strong Base. Its hydrolysis produces OH⁻ ions, making it basic.
11. Henderson-Hasselbalch equation for acidic buffer is:
a) pH = pKa + log([Salt]/[Acid])
b) pH = pKa - log([Salt]/[Acid])
c) pH = pKb + log([Salt]/[Base])
d) pH = pKa + log([Acid]/[Salt])
Solution: pH = pKa + log([Salt]/[Acid]).
12. Common ion effect is observed when:
a) HCl is added to NaCl solution
b) NaOH is added to HCl solution
c) NH₄OH is added to water
d) NH₄Cl is added to NH₄OH solution
Solution: Adding NH₄Cl (Strong Electrolyte) to NH₄OH (Weak Electrolyte) suppresses dissociation of NH₄OH due to common NH₄⁺ ion.
13. The relation between solubility (S) and solubility product (Ksp) for CaF₂ is:
a) Ksp = S²
b) Ksp = 4S³
c) Ksp = 27S⁴
d) Ksp = S³
Solution: CaF₂ → Ca²⁺ + 2F⁻. (S) (2S)². Ksp = S × 4S² = 4S³.
14. Which of the following is a strong electrolyte?
a) Acetic acid
b) Ammonium hydroxide
c) Hydrochloric acid
d) Carbonic acid
Solution: HCl dissociates completely in water, making it a strong electrolyte.
15. Degree of dissociation (α) for a weak acid is given by Ostwald's dilution law as:
a) α = √(Ka/C)
b) α = Ka/C
c) α = √(C/Ka)
d) α = Ka × C
Solution: For weak electrolytes, α = √(Ka/C).
16. The pH of human blood is approximately:
a) 6.4
b) 7.0
c) 8.2
d) 7.4
Solution: Human blood acts as a buffer solution with a pH around 7.35 - 7.45.
17. Which species can act as both Bronsted acid and Bronsted base?
a) Cl⁻
b) HCO₃⁻
c) H₃O⁺
d) NH₄⁺
Solution: Amphoteric nature: HCO₃⁻ can donate H⁺ (to form CO₃²⁻) or accept H⁺ (to form H₂CO₃).
18. Condition for precipitation is:
a) IP < Ksp
b) IP = Ksp
c) IP > Ksp
d) IP = 0
Solution: Precipitation occurs when Ionic Product (IP) exceeds the Solubility Product (Ksp).
19. If pH of a solution is 3, the hydrogen ion concentration is:
a) 10⁻³ M
b) 10³ M
c) 3 M
d) 0.3 M
Solution: [H⁺] = 10^(-pH) = 10⁻³ M.
20. What is the pH of 10⁻⁸ M HCl solution?
a) 8
b) 6
c) 7
d) 6.96
Solution: H⁺ from HCl = 10⁻⁸, H⁺ from water = 10⁻⁷. Total H⁺ ≈ 1.1 × 10⁻⁷. pH ≈ 6.96 (slightly less than 7).

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